Base | Representation |
---|---|
bin | 110001011111011110… |
… | …011100100000000101 |
3 | 12002011111222001101211 |
4 | 301133132130200011 |
5 | 1332313201033013 |
6 | 40225101051421 |
7 | 3560615436460 |
oct | 613736344005 |
9 | 162144861354 |
10 | 53141424133 |
11 | 2059aa48546 |
12 | a370b56b71 |
13 | 501b83c885 |
14 | 2801a2c2d7 |
15 | 15b057223d |
hex | c5f79c805 |
53141424133 has 8 divisors (see below), whose sum is σ = 60739143680. Its totient is φ = 45545226480.
The previous prime is 53141424131. The next prime is 53141424137. The reversal of 53141424133 is 33142414135.
53141424133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53141424133 - 21 = 53141424131 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53141424095 and 53141424104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53141424131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 304638 + ... + 446191.
It is an arithmetic number, because the mean of its divisors is an integer number (7592392960).
Almost surely, 253141424133 is an apocalyptic number.
It is an amenable number.
53141424133 is a deficient number, since it is larger than the sum of its proper divisors (7597719547).
53141424133 is a wasteful number, since it uses less digits than its factorization.
53141424133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 760947.
The product of its digits is 17280, while the sum is 31.
Adding to 53141424133 its reverse (33142414135), we get a palindrome (86283838268).
The spelling of 53141424133 in words is "fifty-three billion, one hundred forty-one million, four hundred twenty-four thousand, one hundred thirty-three".
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