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5314143103441 is a prime number
BaseRepresentation
bin100110101010100101110…
…0111001010100111010001
3200211000201202210020202021
41031111023213022213101
51144031331113302231
615145141133251441
71055635264040314
oct115251347124721
920730652706667
105314143103441
1117697962737a7
12719abb933b81
132c7177057823
141452c4db297b
159337687e811
hex4d54b9ca9d1

5314143103441 has 2 divisors, whose sum is σ = 5314143103442. Its totient is φ = 5314143103440.

The previous prime is 5314143103439. The next prime is 5314143103463. The reversal of 5314143103441 is 1443013414135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4588913730625 + 725229372816 = 2142175^2 + 851604^2 .

It is a cyclic number.

It is not a de Polignac number, because 5314143103441 - 21 = 5314143103439 is a prime.

Together with 5314143103439, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 5314143103397 and 5314143103406.

It is not a weakly prime, because it can be changed into another prime (5314143103421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2657071551720 + 2657071551721.

It is an arithmetic number, because the mean of its divisors is an integer number (2657071551721).

Almost surely, 25314143103441 is an apocalyptic number.

It is an amenable number.

5314143103441 is a deficient number, since it is larger than the sum of its proper divisors (1).

5314143103441 is an equidigital number, since it uses as much as digits as its factorization.

5314143103441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 5314143103441 its reverse (1443013414135), we get a palindrome (6757156517576).

The spelling of 5314143103441 in words is "five trillion, three hundred fourteen billion, one hundred forty-three million, one hundred three thousand, four hundred forty-one".