Base | Representation |
---|---|
bin | 110001011111100010… |
… | …100101111111000111 |
3 | 12002011121000022001212 |
4 | 301133202211333013 |
5 | 1332313440332214 |
6 | 40225140242035 |
7 | 3560630616014 |
oct | 613742457707 |
9 | 162147008055 |
10 | 53142511559 |
11 | 205a0620545 |
12 | a3713a031b |
13 | 501bb30817 |
14 | 2801c3270b |
15 | 15b06d953e |
hex | c5f8a5fc7 |
53142511559 has 2 divisors, whose sum is σ = 53142511560. Its totient is φ = 53142511558.
The previous prime is 53142511507. The next prime is 53142511607. The reversal of 53142511559 is 95511524135.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53142511559 is a prime.
It is a super-2 number, since 2×531425115592 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53142511259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26571255779 + 26571255780.
It is an arithmetic number, because the mean of its divisors is an integer number (26571255780).
Almost surely, 253142511559 is an apocalyptic number.
53142511559 is a deficient number, since it is larger than the sum of its proper divisors (1).
53142511559 is an equidigital number, since it uses as much as digits as its factorization.
53142511559 is an evil number, because the sum of its binary digits is even.
The product of its digits is 135000, while the sum is 41.
The spelling of 53142511559 in words is "fifty-three billion, one hundred forty-two million, five hundred eleven thousand, five hundred fifty-nine".
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