Base | Representation |
---|---|
bin | 1111011101110111011… |
… | …01100010101010001001 |
3 | 1212210201021210002221222 |
4 | 13232323231202222021 |
5 | 32201332121131431 |
6 | 1044045150411425 |
7 | 53252223431504 |
oct | 7567355425211 |
9 | 1783637702858 |
10 | 531430255241 |
11 | 195418585456 |
12 | 86bb2b00b75 |
13 | 3b162925842 |
14 | 1ba155b813b |
15 | dc550cb57b |
hex | 7bbbb62a89 |
531430255241 has 2 divisors, whose sum is σ = 531430255242. Its totient is φ = 531430255240.
The previous prime is 531430255211. The next prime is 531430255249. The reversal of 531430255241 is 142552034135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 497559533641 + 33870721600 = 705379^2 + 184040^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-531430255241 is a prime.
It is not a weakly prime, because it can be changed into another prime (531430255249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265715127620 + 265715127621.
It is an arithmetic number, because the mean of its divisors is an integer number (265715127621).
Almost surely, 2531430255241 is an apocalyptic number.
It is an amenable number.
531430255241 is a deficient number, since it is larger than the sum of its proper divisors (1).
531430255241 is an equidigital number, since it uses as much as digits as its factorization.
531430255241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 531430255241 its reverse (142552034135), we get a palindrome (673982289376).
The spelling of 531430255241 in words is "five hundred thirty-one billion, four hundred thirty million, two hundred fifty-five thousand, two hundred forty-one".
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