Base | Representation |
---|---|
bin | 1111011101111001111… |
… | …00110110001000111101 |
3 | 1212210202201220022100022 |
4 | 13232330330312020331 |
5 | 32201402431410123 |
6 | 1044051212141525 |
7 | 53252565225362 |
oct | 7567474661075 |
9 | 1783681808308 |
10 | 531451044413 |
11 | 195429294693 |
12 | 86bb9a678a5 |
13 | 3b167024223 |
14 | 1ba1826a469 |
15 | dc56d361c8 |
hex | 7bbcf3623d |
531451044413 has 2 divisors, whose sum is σ = 531451044414. Its totient is φ = 531451044412.
The previous prime is 531451044409. The next prime is 531451044461. The reversal of 531451044413 is 314440154135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 492743629849 + 38707414564 = 701957^2 + 196742^2 .
It is a cyclic number.
It is not a de Polignac number, because 531451044413 - 22 = 531451044409 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531451044403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265725522206 + 265725522207.
It is an arithmetic number, because the mean of its divisors is an integer number (265725522207).
Almost surely, 2531451044413 is an apocalyptic number.
It is an amenable number.
531451044413 is a deficient number, since it is larger than the sum of its proper divisors (1).
531451044413 is an equidigital number, since it uses as much as digits as its factorization.
531451044413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 531451044413 its reverse (314440154135), we get a palindrome (845891198548).
The spelling of 531451044413 in words is "five hundred thirty-one billion, four hundred fifty-one million, forty-four thousand, four hundred thirteen".
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