Base | Representation |
---|---|
bin | 111100011010111001101111… |
… | …1101011110001001110001011 |
3 | 2120200202100220200011121221110 |
4 | 1320311303133223301032023 |
5 | 1024124442214014000021 |
6 | 5122154422344541403 |
7 | 216641635505354241 |
oct | 17065633753611613 |
9 | 2520670820147843 |
10 | 531463006000011 |
11 | 1443822167474a8 |
12 | 4b735111481863 |
13 | 19a71991b6c4c7 |
14 | 9534d37bd0791 |
15 | 416988be16476 |
hex | 1e35cdfaf138b |
531463006000011 has 8 divisors (see below), whose sum is σ = 710231503843840. Its totient is φ = 353501589411432.
The previous prime is 531463005999979. The next prime is 531463006000051. The reversal of 531463006000011 is 110000600364135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 531463006000011 - 25 = 531463005999979 is a prime.
It is a super-2 number, since 2×5314630060000112 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (531463006000051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 201770312275 + ... + 201770314908.
It is an arithmetic number, because the mean of its divisors is an integer number (88778937980480).
Almost surely, 2531463006000011 is an apocalyptic number.
531463006000011 is a deficient number, since it is larger than the sum of its proper divisors (178768497843829).
531463006000011 is a wasteful number, since it uses less digits than its factorization.
531463006000011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 403540627625.
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 531463006000011 its reverse (110000600364135), we get a palindrome (641463606364146).
The spelling of 531463006000011 in words is "five hundred thirty-one trillion, four hundred sixty-three billion, six million, eleven", and thus it is an aban number.
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