Base | Representation |
---|---|
bin | 110001011111110100… |
… | …001010100010001011 |
3 | 12002011220200022111221 |
4 | 301133310022202023 |
5 | 1332321130231312 |
6 | 40225423102511 |
7 | 3561015022015 |
oct | 613764124213 |
9 | 162156608457 |
10 | 53147117707 |
11 | 205a3187182 |
12 | a372a41a37 |
13 | 501ca84258 |
14 | 28026b11b5 |
15 | 15b0ce9207 |
hex | c5fd0a88b |
53147117707 has 2 divisors, whose sum is σ = 53147117708. Its totient is φ = 53147117706.
The previous prime is 53147117693. The next prime is 53147117711. The reversal of 53147117707 is 70771174135.
53147117707 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53147117707 is a prime.
It is a super-2 number, since 2×531471177072 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53147117747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26573558853 + 26573558854.
It is an arithmetic number, because the mean of its divisors is an integer number (26573558854).
Almost surely, 253147117707 is an apocalyptic number.
53147117707 is a deficient number, since it is larger than the sum of its proper divisors (1).
53147117707 is an equidigital number, since it uses as much as digits as its factorization.
53147117707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144060, while the sum is 43.
The spelling of 53147117707 in words is "fifty-three billion, one hundred forty-seven million, one hundred seventeen thousand, seven hundred seven".
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