Base | Representation |
---|---|
bin | 110001011111110100… |
… | …001010100001111101 |
3 | 12002011220200022111102 |
4 | 301133310022201331 |
5 | 1332321130231233 |
6 | 40225423102445 |
7 | 3561015021665 |
oct | 613764124175 |
9 | 162156608442 |
10 | 53147117693 |
11 | 205a318716a |
12 | a372a41a25 |
13 | 501ca84247 |
14 | 28026b11a5 |
15 | 15b0ce91e8 |
hex | c5fd0a87d |
53147117693 has 2 divisors, whose sum is σ = 53147117694. Its totient is φ = 53147117692.
The previous prime is 53147117689. The next prime is 53147117707. The reversal of 53147117693 is 39671174135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28972465369 + 24174652324 = 170213^2 + 155482^2 .
It is a cyclic number.
It is not a de Polignac number, because 53147117693 - 22 = 53147117689 is a prime.
It is a super-2 number, since 2×531471176932 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53144117693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26573558846 + 26573558847.
It is an arithmetic number, because the mean of its divisors is an integer number (26573558847).
Almost surely, 253147117693 is an apocalyptic number.
It is an amenable number.
53147117693 is a deficient number, since it is larger than the sum of its proper divisors (1).
53147117693 is an equidigital number, since it uses as much as digits as its factorization.
53147117693 is an evil number, because the sum of its binary digits is even.
The product of its digits is 476280, while the sum is 47.
The spelling of 53147117693 in words is "fifty-three billion, one hundred forty-seven million, one hundred seventeen thousand, six hundred ninety-three".
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