Base | Representation |
---|---|
bin | 11000001010110111101010… |
… | …10100111000010111110100 |
3 | 20222012002112202102212020212 |
4 | 30011123311110320113310 |
5 | 23431302241022244104 |
6 | 305012443012444552 |
7 | 14123651366064233 |
oct | 1405336524702764 |
9 | 228162482385225 |
10 | 53150041212404 |
11 | 15a31895711454 |
12 | 5b64a01319758 |
13 | 2387048201966 |
14 | d1a69353cb1a |
15 | 62284b8c436e |
hex | 3056f55385f4 |
53150041212404 has 24 divisors (see below), whose sum is σ = 93591376973640. Its totient is φ = 26409782964224.
The previous prime is 53150041212397. The next prime is 53150041212409. The reversal of 53150041212404 is 40421214005135.
It can be written as a sum of positive squares in 4 ways, for example, as 36093636808804 + 17056404403600 = 6007798^2 + 4129940^2 .
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53150041212409) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15322469 + ... + 18468300.
It is an arithmetic number, because the mean of its divisors is an integer number (3899640707235).
Almost surely, 253150041212404 is an apocalyptic number.
It is an amenable number.
53150041212404 is a deficient number, since it is larger than the sum of its proper divisors (40441335761236).
53150041212404 is a wasteful number, since it uses less digits than its factorization.
53150041212404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33793219 (or 33793217 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 53150041212404 its reverse (40421214005135), we get a palindrome (93571255217539).
The spelling of 53150041212404 in words is "fifty-three trillion, one hundred fifty billion, forty-one million, two hundred twelve thousand, four hundred four".
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