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53150324541 = 317716774847
BaseRepresentation
bin110001100000000000…
…011001011100111101
312002012010201020110120
4301200000121130331
51332322440341131
640230015525153
73561054206256
oct614000313475
9162163636416
1053150324541
11205a4a77556
12a373b297b9
135020637aa2
142802ca7b2d
1515b122e496
hexc6001973d

53150324541 has 4 divisors (see below), whose sum is σ = 70867099392. Its totient is φ = 35433549692.

The previous prime is 53150324533. The next prime is 53150324599. The reversal of 53150324541 is 14542305135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53150324541 - 23 = 53150324533 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53150304541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8858387421 + ... + 8858387426.

It is an arithmetic number, because the mean of its divisors is an integer number (17716774848).

Almost surely, 253150324541 is an apocalyptic number.

It is an amenable number.

53150324541 is a deficient number, since it is larger than the sum of its proper divisors (17716774851).

53150324541 is a wasteful number, since it uses less digits than its factorization.

53150324541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17716774850.

The product of its (nonzero) digits is 36000, while the sum is 33.

Adding to 53150324541 its reverse (14542305135), we get a palindrome (67692629676).

The spelling of 53150324541 in words is "fifty-three billion, one hundred fifty million, three hundred twenty-four thousand, five hundred forty-one".

Divisors: 1 3 17716774847 53150324541