Base | Representation |
---|---|
bin | 110001100000000000… |
… | …101101001000001110 |
3 | 12002012010212100000111 |
4 | 301200000231020032 |
5 | 1332323000431014 |
6 | 40230021350234 |
7 | 3561054663241 |
oct | 614000551016 |
9 | 162163770014 |
10 | 53150405134 |
11 | 205a5022062 |
12 | a373b6837a |
13 | 5020665688 |
14 | 2802cc9258 |
15 | 15b12482c4 |
hex | c6002d20e |
53150405134 has 4 divisors (see below), whose sum is σ = 79725607704. Its totient is φ = 26575202566.
The previous prime is 53150405111. The next prime is 53150405179. The reversal of 53150405134 is 43150405135.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 53150405096 and 53150405105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13287601282 + ... + 13287601285.
It is an arithmetic number, because the mean of its divisors is an integer number (19931401926).
Almost surely, 253150405134 is an apocalyptic number.
53150405134 is a deficient number, since it is larger than the sum of its proper divisors (26575202570).
53150405134 is a wasteful number, since it uses less digits than its factorization.
53150405134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26575202569.
The product of its (nonzero) digits is 18000, while the sum is 31.
Subtracting from 53150405134 its reverse (43150405135), we obtain a palindrome (9999999999).
The spelling of 53150405134 in words is "fifty-three billion, one hundred fifty million, four hundred five thousand, one hundred thirty-four".
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