Base | Representation |
---|---|
bin | 110001100000000100… |
… | …001000000111010101 |
3 | 12002012012112220102111 |
4 | 301200010020013111 |
5 | 1332323213131401 |
6 | 40230052511021 |
7 | 3561065420302 |
oct | 614004100725 |
9 | 162165486374 |
10 | 53151302101 |
11 | 205a5584a57 |
12 | a37431b471 |
13 | 50208baa21 |
14 | 28030800a9 |
15 | 15b1373e51 |
hex | c601081d5 |
53151302101 has 2 divisors, whose sum is σ = 53151302102. Its totient is φ = 53151302100.
The previous prime is 53151302063. The next prime is 53151302131. The reversal of 53151302101 is 10120315135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49166410225 + 3984891876 = 221735^2 + 63126^2 .
It is a cyclic number.
It is not a de Polignac number, because 53151302101 - 211 = 53151300053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53151302131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26575651050 + 26575651051.
It is an arithmetic number, because the mean of its divisors is an integer number (26575651051).
Almost surely, 253151302101 is an apocalyptic number.
It is an amenable number.
53151302101 is a deficient number, since it is larger than the sum of its proper divisors (1).
53151302101 is an equidigital number, since it uses as much as digits as its factorization.
53151302101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 53151302101 its reverse (10120315135), we get a palindrome (63271617236).
The spelling of 53151302101 in words is "fifty-three billion, one hundred fifty-one million, three hundred two thousand, one hundred one".
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