Base | Representation |
---|---|
bin | 11000001010111100010000… |
… | …00000001100111000001011 |
3 | 20222012022220020220222000022 |
4 | 30011132020000030320023 |
5 | 23431322311010321443 |
6 | 305013531120531055 |
7 | 14124066356562011 |
oct | 1405361000147013 |
9 | 228168806828008 |
10 | 53152502042123 |
11 | 15a329387a1220 |
12 | 5b65389480a8b |
13 | 238734ac98113 |
14 | d1a8482b48b1 |
15 | 622942963e68 |
hex | 30578800ce0b |
53152502042123 has 32 divisors (see below), whose sum is σ = 58311210507264. Its totient is φ = 48048966000000.
The previous prime is 53152502042069. The next prime is 53152502042161. The reversal of 53152502042123 is 32124020525135.
It is a cyclic number.
It is not a de Polignac number, because 53152502042123 - 28 = 53152502041867 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53152502042323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8641275098 + ... + 8641281248.
It is an arithmetic number, because the mean of its divisors is an integer number (1822225328352).
Almost surely, 253152502042123 is an apocalyptic number.
53152502042123 is a deficient number, since it is larger than the sum of its proper divisors (5158708465141).
53152502042123 is a wasteful number, since it uses less digits than its factorization.
53152502042123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11387.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 53152502042123 its reverse (32124020525135), we get a palindrome (85276522567258).
The spelling of 53152502042123 in words is "fifty-three trillion, one hundred fifty-two billion, five hundred two million, forty-two thousand, one hundred twenty-three".
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