Base | Representation |
---|---|
bin | 1001111001101110… |
… | …00011011111000111 |
3 | 111201111001102120221 |
4 | 10330313003133013 |
5 | 41341401014310 |
6 | 2235301005211 |
7 | 245510346616 |
oct | 47467033707 |
9 | 14644042527 |
10 | 5316032455 |
11 | 2288841958 |
12 | 10443b3807 |
13 | 669480c46 |
14 | 38604987d |
15 | 211a80ada |
hex | 13cdc37c7 |
5316032455 has 16 divisors (see below), whose sum is σ = 6544812960. Its totient is φ = 4143720448.
The previous prime is 5316032443. The next prime is 5316032467. The reversal of 5316032455 is 5542306135.
It is an interprime number because it is at equal distance from previous prime (5316032443) and next prime (5316032467).
It is a cyclic number.
It is not a de Polignac number, because 5316032455 - 27 = 5316032327 is a prime.
It is a super-2 number, since 2×53160324552 = 56520402125226654050, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5316032455.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46402 + ... + 113071.
It is an arithmetic number, because the mean of its divisors is an integer number (409050810).
Almost surely, 25316032455 is an apocalyptic number.
5316032455 is a deficient number, since it is larger than the sum of its proper divisors (1228780505).
5316032455 is a wasteful number, since it uses less digits than its factorization.
5316032455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159650.
The product of its (nonzero) digits is 54000, while the sum is 34.
The square root of 5316032455 is about 72911.1271000524. The cubic root of 5316032455 is about 1745.2696693003.
The spelling of 5316032455 in words is "five billion, three hundred sixteen million, thirty-two thousand, four hundred fifty-five".
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