Base | Representation |
---|---|
bin | 1111011110001101010… |
… | …00001011101111110011 |
3 | 1212211012001101211102002 |
4 | 13233012220023233303 |
5 | 32202221012300201 |
6 | 1044115252044215 |
7 | 53256606225416 |
oct | 7570650135763 |
9 | 1784161354362 |
10 | 531613400051 |
11 | 1955019a58a8 |
12 | 8704430366b |
13 | 3b19185ac56 |
14 | 1ba31a4db7d |
15 | dc6620676b |
hex | 7bc6a0bbf3 |
531613400051 has 8 divisors (see below), whose sum is σ = 531880398000. Its totient is φ = 531346466560.
The previous prime is 531613400029. The next prime is 531613400063. The reversal of 531613400051 is 150004316135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 531613400051 - 26 = 531613399987 is a prime.
It is a super-2 number, since 2×5316134000512 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 531613399987 and 531613400023.
It is not an unprimeable number, because it can be changed into a prime (531613400011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25996991 + ... + 26017431.
It is an arithmetic number, because the mean of its divisors is an integer number (66485049750).
Almost surely, 2531613400051 is an apocalyptic number.
531613400051 is a deficient number, since it is larger than the sum of its proper divisors (266997949).
531613400051 is a wasteful number, since it uses less digits than its factorization.
531613400051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32229.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 531613400051 its reverse (150004316135), we get a palindrome (681617716186).
The spelling of 531613400051 in words is "five hundred thirty-one billion, six hundred thirteen million, four hundred thousand, fifty-one".
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