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531613400029 is a prime number
BaseRepresentation
bin1111011110001101010…
…00001011101111011101
31212211012001101211101021
413233012220023233131
532202221012300104
61044115252044141
753256606225355
oct7570650135735
91784161354337
10531613400029
111955019a5888
1287044303651
133b19185ac3a
141ba31a4db65
15dc66206754
hex7bc6a0bbdd

531613400029 has 2 divisors, whose sum is σ = 531613400030. Its totient is φ = 531613400028.

The previous prime is 531613400023. The next prime is 531613400063. The reversal of 531613400029 is 920004316135.

It is an a-pointer prime, because the next prime (531613400063) can be obtained adding 531613400029 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 507642000100 + 23971399929 = 712490^2 + 154827^2 .

It is a cyclic number.

It is not a de Polignac number, because 531613400029 - 27 = 531613399901 is a prime.

It is a super-2 number, since 2×5316134000292 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 531613399967 and 531613400003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531613400023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265806700014 + 265806700015.

It is an arithmetic number, because the mean of its divisors is an integer number (265806700015).

Almost surely, 2531613400029 is an apocalyptic number.

It is an amenable number.

531613400029 is a deficient number, since it is larger than the sum of its proper divisors (1).

531613400029 is an equidigital number, since it uses as much as digits as its factorization.

531613400029 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 34.

The spelling of 531613400029 in words is "five hundred thirty-one billion, six hundred thirteen million, four hundred thousand, twenty-nine".