Base | Representation |
---|---|
bin | 110001100000110100… |
… | …111111001001000001 |
3 | 12002020002122122002222 |
4 | 301200310333021001 |
5 | 1332340003013101 |
6 | 40231231220425 |
7 | 3561312324263 |
oct | 614064771101 |
9 | 162202578088 |
10 | 53164110401 |
11 | 20601833026 |
12 | a378677715 |
13 | 50234538bc |
14 | 2804a55b33 |
15 | 15b255401b |
hex | c60d3f241 |
53164110401 has 2 divisors, whose sum is σ = 53164110402. Its totient is φ = 53164110400.
The previous prime is 53164110383. The next prime is 53164110407. The reversal of 53164110401 is 10401146135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52992500401 + 171610000 = 230201^2 + 13100^2 .
It is a cyclic number.
It is not a de Polignac number, because 53164110401 - 214 = 53164094017 is a prime.
It is not a weakly prime, because it can be changed into another prime (53164110407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26582055200 + 26582055201.
It is an arithmetic number, because the mean of its divisors is an integer number (26582055201).
Almost surely, 253164110401 is an apocalyptic number.
It is an amenable number.
53164110401 is a deficient number, since it is larger than the sum of its proper divisors (1).
53164110401 is an equidigital number, since it uses as much as digits as its factorization.
53164110401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 53164110401 its reverse (10401146135), we get a palindrome (63565256536).
The spelling of 53164110401 in words is "fifty-three billion, one hundred sixty-four million, one hundred ten thousand, four hundred one".
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