Base | Representation |
---|---|
bin | 110001100000110100… |
… | …111111001001000111 |
3 | 12002020002122122010012 |
4 | 301200310333021013 |
5 | 1332340003013112 |
6 | 40231231220435 |
7 | 3561312324302 |
oct | 614064771107 |
9 | 162202578105 |
10 | 53164110407 |
11 | 20601833031 |
12 | a37867771b |
13 | 50234538c5 |
14 | 2804a55b39 |
15 | 15b2554022 |
hex | c60d3f247 |
53164110407 has 2 divisors, whose sum is σ = 53164110408. Its totient is φ = 53164110406.
The previous prime is 53164110401. The next prime is 53164110473. The reversal of 53164110407 is 70401146135.
53164110407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53164110407 - 26 = 53164110343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53164110401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26582055203 + 26582055204.
It is an arithmetic number, because the mean of its divisors is an integer number (26582055204).
Almost surely, 253164110407 is an apocalyptic number.
53164110407 is a deficient number, since it is larger than the sum of its proper divisors (1).
53164110407 is an equidigital number, since it uses as much as digits as its factorization.
53164110407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
The spelling of 53164110407 in words is "fifty-three billion, one hundred sixty-four million, one hundred ten thousand, four hundred seven".
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