Search a number
-
+
53171119404 = 2232132953193383
BaseRepresentation
bin110001100001001111…
…101110010100101100
312002020120211201122200
4301201033232110230
51332343301310104
640232041341500
73561426025554
oct614117562454
9162216751580
1053171119404
112060578aa97
12a37aa97890
135024a38c40
14280595c164
1515b2e8ab39
hexc613ee52c

53171119404 has 288 divisors, whose sum is σ = 153750804480. Its totient is φ = 15377596416.

The previous prime is 53171119381. The next prime is 53171119429. The reversal of 53171119404 is 40491117135.

53171119404 is a `hidden beast` number, since 531 + 7 + 1 + 119 + 4 + 0 + 4 = 666.

53171119404 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 138827797 + ... + 138828179.

It is an arithmetic number, because the mean of its divisors is an integer number (533856960).

Almost surely, 253171119404 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53171119404, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (76875402240).

53171119404 is an abundant number, since it is smaller than the sum of its proper divisors (100579685076).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53171119404 is a wasteful number, since it uses less digits than its factorization.

53171119404 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 681 (or 676 counting only the distinct ones).

The product of its (nonzero) digits is 15120, while the sum is 36.

The spelling of 53171119404 in words is "fifty-three billion, one hundred seventy-one million, one hundred nineteen thousand, four hundred four".