Base | Representation |
---|---|
bin | 1111011110110101010… |
… | …00111001110100101101 |
3 | 1212212001110010211120111 |
4 | 13233122220321310231 |
5 | 32203412434224401 |
6 | 1044212444020021 |
7 | 53301124012111 |
oct | 7573250716455 |
9 | 1785043124514 |
10 | 531949133101 |
11 | 195664466031 |
12 | 87118831611 |
13 | 3b21628a369 |
14 | 1ba64485741 |
15 | dc85922e51 |
hex | 7bdaa39d2d |
531949133101 has 2 divisors, whose sum is σ = 531949133102. Its totient is φ = 531949133100.
The previous prime is 531949133087. The next prime is 531949133113. The reversal of 531949133101 is 101331949135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 485668216201 + 46280916900 = 696899^2 + 215130^2 .
It is a cyclic number.
It is not a de Polignac number, because 531949133101 - 217 = 531949002029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531949133801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265974566550 + 265974566551.
It is an arithmetic number, because the mean of its divisors is an integer number (265974566551).
Almost surely, 2531949133101 is an apocalyptic number.
It is an amenable number.
531949133101 is a deficient number, since it is larger than the sum of its proper divisors (1).
531949133101 is an equidigital number, since it uses as much as digits as its factorization.
531949133101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43740, while the sum is 40.
The spelling of 531949133101 in words is "five hundred thirty-one billion, nine hundred forty-nine million, one hundred thirty-three thousand, one hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •