Base | Representation |
---|---|
bin | 11000001100010101100010… |
… | …00111010011100001111101 |
3 | 20222100220121212220011201222 |
4 | 30012022301013103201331 |
5 | 23433113443210113433 |
6 | 305051535412443125 |
7 | 14130414260152061 |
oct | 1406126107234175 |
9 | 228326555804658 |
10 | 53200436410493 |
11 | 15a511a646a699 |
12 | 5b727266194a5 |
13 | 238ba19ac13b8 |
14 | d1ccb4543aa1 |
15 | 623ceacceb98 |
hex | 3062b11d387d |
53200436410493 has 2 divisors, whose sum is σ = 53200436410494. Its totient is φ = 53200436410492.
The previous prime is 53200436410397. The next prime is 53200436410549. The reversal of 53200436410493 is 39401463400235.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46857830897284 + 6342605513209 = 6845278^2 + 2518453^2 .
It is a cyclic number.
It is not a de Polignac number, because 53200436410493 - 222 = 53200432216189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53200436410393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26600218205246 + 26600218205247.
It is an arithmetic number, because the mean of its divisors is an integer number (26600218205247).
Almost surely, 253200436410493 is an apocalyptic number.
It is an amenable number.
53200436410493 is a deficient number, since it is larger than the sum of its proper divisors (1).
53200436410493 is an equidigital number, since it uses as much as digits as its factorization.
53200436410493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 933120, while the sum is 44.
The spelling of 53200436410493 in words is "fifty-three trillion, two hundred billion, four hundred thirty-six million, four hundred ten thousand, four hundred ninety-three".
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