Base | Representation |
---|---|
bin | 11000001100010110000101… |
… | …10101001110111100011001 |
3 | 20222100221101121020011112010 |
4 | 30012023002311032330121 |
5 | 23433120100304204001 |
6 | 305052025111540133 |
7 | 14130424526566341 |
oct | 1406130265167431 |
9 | 228327347204463 |
10 | 53200733663001 |
11 | 15a51339237921 |
12 | 5b727aa08a649 |
13 | 238ba66569762 |
14 | d1cd01bddd21 |
15 | 623d16e498d6 |
hex | 3062c2d4ef19 |
53200733663001 has 24 divisors (see below), whose sum is σ = 75353296731264. Its totient is φ = 33380439988480.
The previous prime is 53200733662991. The next prime is 53200733663009. The reversal of 53200733663001 is 10036633700235.
It is not a de Polignac number, because 53200733663001 - 25 = 53200733662969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53200733663009) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 79527151 + ... + 80193323.
It is an arithmetic number, because the mean of its divisors is an integer number (3139720697136).
Almost surely, 253200733663001 is an apocalyptic number.
53200733663001 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
It is an amenable number.
53200733663001 is a deficient number, since it is larger than the sum of its proper divisors (22152563068263).
53200733663001 is a wasteful number, since it uses less digits than its factorization.
53200733663001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 758321 (or 758304 counting only the distinct ones).
The product of its (nonzero) digits is 204120, while the sum is 39.
The spelling of 53200733663001 in words is "fifty-three trillion, two hundred billion, seven hundred thirty-three million, six hundred sixty-three thousand, one".
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