Base | Representation |
---|---|
bin | 1111011110111100111… |
… | …00011000101011100111 |
3 | 1212212012220020121021202 |
4 | 13233132130120223213 |
5 | 32204030304213422 |
6 | 1044223044033115 |
7 | 53302530356561 |
oct | 7573634305347 |
9 | 1785186217252 |
10 | 532012960487 |
11 | 1956974a0538 |
12 | 8713609279b |
13 | 3b226577448 |
14 | 1ba6cb3c331 |
15 | dc8b32eb92 |
hex | 7bde718ae7 |
532012960487 has 2 divisors, whose sum is σ = 532012960488. Its totient is φ = 532012960486.
The previous prime is 532012960411. The next prime is 532012960543. The reversal of 532012960487 is 784069210235.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 532012960487 - 234 = 514833091303 is a prime.
It is a super-2 number, since 2×5320129604872 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (532012969487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266006480243 + 266006480244.
It is an arithmetic number, because the mean of its divisors is an integer number (266006480244).
It is a 1-persistent number, because it is pandigital, but 2⋅532012960487 = 1064025920974 is not.
Almost surely, 2532012960487 is an apocalyptic number.
532012960487 is a deficient number, since it is larger than the sum of its proper divisors (1).
532012960487 is an equidigital number, since it uses as much as digits as its factorization.
532012960487 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 725760, while the sum is 47.
The spelling of 532012960487 in words is "five hundred thirty-two billion, twelve million, nine hundred sixty thousand, four hundred eighty-seven".
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