Base | Representation |
---|---|
bin | 100110101101011001100… |
… | …0111111011011001010001 |
3 | 200211121022010022201202201 |
4 | 1031122303013323121101 |
5 | 1144131204211244101 |
6 | 15152015435443201 |
7 | 1056240613625143 |
oct | 115326307733121 |
9 | 20747263281681 |
10 | 5320174712401 |
11 | 1771300a2389a |
12 | 71b1038b6501 |
13 | 2c78c883ca03 |
14 | 1456d808cc93 |
15 | 935cb15ce01 |
hex | 4d6b31fb651 |
5320174712401 has 2 divisors, whose sum is σ = 5320174712402. Its totient is φ = 5320174712400.
The previous prime is 5320174712389. The next prime is 5320174712443. The reversal of 5320174712401 is 1042174710235.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3658034934801 + 1662139777600 = 1912599^2 + 1289240^2 .
It is a cyclic number.
It is not a de Polignac number, because 5320174712401 - 27 = 5320174712273 is a prime.
It is not a weakly prime, because it can be changed into another prime (5320174713401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660087356200 + 2660087356201.
It is an arithmetic number, because the mean of its divisors is an integer number (2660087356201).
Almost surely, 25320174712401 is an apocalyptic number.
It is an amenable number.
5320174712401 is a deficient number, since it is larger than the sum of its proper divisors (1).
5320174712401 is an equidigital number, since it uses as much as digits as its factorization.
5320174712401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47040, while the sum is 37.
The spelling of 5320174712401 in words is "five trillion, three hundred twenty billion, one hundred seventy-four million, seven hundred twelve thousand, four hundred one".
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