Base | Representation |
---|---|
bin | 100110101101011001100… |
… | …0111111011011001111011 |
3 | 200211121022010022201211021 |
4 | 1031122303013323121323 |
5 | 1144131204211244233 |
6 | 15152015435443311 |
7 | 1056240613625233 |
oct | 115326307733173 |
9 | 20747263281737 |
10 | 5320174712443 |
11 | 1771300a23928 |
12 | 71b1038b6537 |
13 | 2c78c883ca36 |
14 | 1456d808ccc3 |
15 | 935cb15ce2d |
hex | 4d6b31fb67b |
5320174712443 has 2 divisors, whose sum is σ = 5320174712444. Its totient is φ = 5320174712442.
The previous prime is 5320174712401. The next prime is 5320174712449. The reversal of 5320174712443 is 3442174710235.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5320174712443 - 237 = 5182735758971 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5320174712443.
It is not a weakly prime, because it can be changed into another prime (5320174712449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660087356221 + 2660087356222.
It is an arithmetic number, because the mean of its divisors is an integer number (2660087356222).
Almost surely, 25320174712443 is an apocalyptic number.
5320174712443 is a deficient number, since it is larger than the sum of its proper divisors (1).
5320174712443 is an equidigital number, since it uses as much as digits as its factorization.
5320174712443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 564480, while the sum is 43.
The spelling of 5320174712443 in words is "five trillion, three hundred twenty billion, one hundred seventy-four million, seven hundred twelve thousand, four hundred forty-three".
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