Base | Representation |
---|---|
bin | 1100101011110… |
… | …0101101100001 |
3 | 10201002221002121 |
4 | 3022330231201 |
5 | 102104424021 |
6 | 5140144241 |
7 | 1214131114 |
oct | 312745541 |
9 | 121087077 |
10 | 53201761 |
11 | 280382a8 |
12 | 15998081 |
13 | b039842 |
14 | 70cc57b |
15 | 4a0d741 |
hex | 32bcb61 |
53201761 has 2 divisors, whose sum is σ = 53201762. Its totient is φ = 53201760.
The previous prime is 53201749. The next prime is 53201773. The reversal of 53201761 is 16710235.
It is a balanced prime because it is at equal distance from previous prime (53201749) and next prime (53201773).
It can be written as a sum of positive squares in only one way, i.e., 51624225 + 1577536 = 7185^2 + 1256^2 .
It is a cyclic number.
It is not a de Polignac number, because 53201761 - 29 = 53201249 is a prime.
It is a super-2 number, since 2×532017612 = 5660854747002242, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53201741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26600880 + 26600881.
It is an arithmetic number, because the mean of its divisors is an integer number (26600881).
Almost surely, 253201761 is an apocalyptic number.
It is an amenable number.
53201761 is a deficient number, since it is larger than the sum of its proper divisors (1).
53201761 is an equidigital number, since it uses as much as digits as its factorization.
53201761 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 25.
The square root of 53201761 is about 7293.9537289456. The cubic root of 53201761 is about 376.1046208982.
Adding to 53201761 its reverse (16710235), we get a palindrome (69911996).
The spelling of 53201761 in words is "fifty-three million, two hundred one thousand, seven hundred sixty-one".
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