Base | Representation |
---|---|
bin | 111100011110111111100110… |
… | …0111011011000000110101000 |
3 | 2120202202010101010211020002021 |
4 | 1320331333030323120012220 |
5 | 1024213200340000240404 |
6 | 5123305021411314224 |
7 | 220030363460006410 |
oct | 17075771473300650 |
9 | 2522663333736067 |
10 | 532025332040104 |
11 | 144579749079341 |
12 | 4b8060a72ab974 |
13 | 19ab2a09609036 |
14 | 9554240793640 |
15 | 41792ee5b4454 |
hex | 1e3dfcced81a8 |
532025332040104 has 64 divisors (see below), whose sum is σ = 1148652337472640. Its totient is φ = 226295862117120.
The previous prime is 532025332040087. The next prime is 532025332040143. The reversal of 532025332040104 is 401040233520235.
It is a self number, because there is not a number n which added to its sum of digits gives 532025332040104.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42555639 + ... + 53619334.
It is an arithmetic number, because the mean of its divisors is an integer number (17947692773010).
Almost surely, 2532025332040104 is an apocalyptic number.
It is an amenable number.
532025332040104 is an abundant number, since it is smaller than the sum of its proper divisors (616627005432536).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
532025332040104 is a wasteful number, since it uses less digits than its factorization.
532025332040104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96175730 (or 96175726 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 34.
Adding to 532025332040104 its reverse (401040233520235), we get a palindrome (933065565560339).
The spelling of 532025332040104 in words is "five hundred thirty-two trillion, twenty-five billion, three hundred thirty-two million, forty thousand, one hundred four".
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