Base | Representation |
---|---|
bin | 100110101101100001100… |
… | …0111110010111000001101 |
3 | 200211121222211100220010122 |
4 | 1031123003013302320031 |
5 | 1144132231414103343 |
6 | 15152102224314325 |
7 | 1056250353165122 |
oct | 115330307627015 |
9 | 20747884326118 |
10 | 5320443112973 |
11 | 177142948514a |
12 | 71b1797729a5 |
13 | 2c793c325811 |
14 | 145721998749 |
15 | 935e49c9068 |
hex | 4d6c31f2e0d |
5320443112973 has 2 divisors, whose sum is σ = 5320443112974. Its totient is φ = 5320443112972.
The previous prime is 5320443112969. The next prime is 5320443112981. The reversal of 5320443112973 is 3792113440235.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4485233558569 + 835209554404 = 2117837^2 + 913898^2 .
It is a cyclic number.
It is not a de Polignac number, because 5320443112973 - 22 = 5320443112969 is a prime.
It is a super-3 number, since 3×53204431129733 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5320443112373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660221556486 + 2660221556487.
It is an arithmetic number, because the mean of its divisors is an integer number (2660221556487).
Almost surely, 25320443112973 is an apocalyptic number.
It is an amenable number.
5320443112973 is a deficient number, since it is larger than the sum of its proper divisors (1).
5320443112973 is an equidigital number, since it uses as much as digits as its factorization.
5320443112973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 44.
The spelling of 5320443112973 in words is "five trillion, three hundred twenty billion, four hundred forty-three million, one hundred twelve thousand, nine hundred seventy-three".
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