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5320443113119 is a prime number
BaseRepresentation
bin100110101101100001100…
…0111110010111010011111
3200211121222211100220100001
41031123003013302322133
51144132231414104434
615152102224315131
71056250353165421
oct115330307627237
920747884326301
105320443113119
111771429485272
1271b179772aa7
132c793c3258c4
14145721998811
15935e49c9114
hex4d6c31f2e9f

5320443113119 has 2 divisors, whose sum is σ = 5320443113120. Its totient is φ = 5320443113118.

The previous prime is 5320443113071. The next prime is 5320443113123. The reversal of 5320443113119 is 9113113440235.

5320443113119 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5320443113119 - 217 = 5320442982047 is a prime.

It is a super-2 number, since 2×53204431131192 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5320443113179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660221556559 + 2660221556560.

It is an arithmetic number, because the mean of its divisors is an integer number (2660221556560).

Almost surely, 25320443113119 is an apocalyptic number.

5320443113119 is a deficient number, since it is larger than the sum of its proper divisors (1).

5320443113119 is an equidigital number, since it uses as much as digits as its factorization.

5320443113119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 37.

The spelling of 5320443113119 in words is "five trillion, three hundred twenty billion, four hundred forty-three million, one hundred thirteen thousand, one hundred nineteen".