Base | Representation |
---|---|
bin | 100110101101111001010… |
… | …1100010000010101111111 |
3 | 200211201001110002220201101 |
4 | 1031123302230100111333 |
5 | 1144140400221344444 |
6 | 15152313334153531 |
7 | 1056306213623344 |
oct | 115336254202577 |
9 | 20751043086641 |
10 | 5321241199999 |
11 | 17717a8a297aa |
12 | 71b360ab28a7 |
13 | 2c7a38788a6a |
14 | 1457999867cb |
15 | 9363eac43d4 |
hex | 4d6f2b1057f |
5321241199999 has 2 divisors, whose sum is σ = 5321241200000. Its totient is φ = 5321241199998.
The previous prime is 5321241199993. The next prime is 5321241200017. The reversal of 5321241199999 is 9999911421235.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5321241199999 - 213 = 5321241191807 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5321241199999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5321241199993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660620599999 + 2660620600000.
It is an arithmetic number, because the mean of its divisors is an integer number (2660620600000).
Almost surely, 25321241199999 is an apocalyptic number.
5321241199999 is a deficient number, since it is larger than the sum of its proper divisors (1).
5321241199999 is an equidigital number, since it uses as much as digits as its factorization.
5321241199999 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14171760, while the sum is 64.
The spelling of 5321241199999 in words is "five trillion, three hundred twenty-one billion, two hundred forty-one million, one hundred ninety-nine thousand, nine hundred ninety-nine".
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