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53224410433 is a prime number
BaseRepresentation
bin110001100100011011…
…000000110101000001
312002101022010012012111
4301210123000311001
51333000422113213
640241223455321
73562644011155
oct614433006501
9162338105174
1053224410433
1120632879367
12a3948b7541
135032aa72ac
14280ca71065
1515b79b5a3d
hexc646c0d41

53224410433 has 2 divisors, whose sum is σ = 53224410434. Its totient is φ = 53224410432.

The previous prime is 53224410419. The next prime is 53224410439. The reversal of 53224410433 is 33401442235.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29197240384 + 24027170049 = 170872^2 + 155007^2 .

It is a cyclic number.

It is not a de Polignac number, because 53224410433 - 29 = 53224409921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53224410395 and 53224410404.

It is not a weakly prime, because it can be changed into another prime (53224410439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26612205216 + 26612205217.

It is an arithmetic number, because the mean of its divisors is an integer number (26612205217).

Almost surely, 253224410433 is an apocalyptic number.

It is an amenable number.

53224410433 is a deficient number, since it is larger than the sum of its proper divisors (1).

53224410433 is an equidigital number, since it uses as much as digits as its factorization.

53224410433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 53224410433 its reverse (33401442235), we get a palindrome (86625852668).

The spelling of 53224410433 in words is "fifty-three billion, two hundred twenty-four million, four hundred ten thousand, four hundred thirty-three".