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53230620433 is a prime number
BaseRepresentation
bin110001100100110010…
…101100111100010001
312002101201210200201111
4301210302230330101
51333004014323213
640242004533321
73563050544134
oct614462547421
9162351720644
1053230620433
112063632aaa1
12a3969b1241
13503416ca53
14280d80a21b
1515b82e0a3d
hexc64cacf11

53230620433 has 2 divisors, whose sum is σ = 53230620434. Its totient is φ = 53230620432.

The previous prime is 53230620427. The next prime is 53230620467. The reversal of 53230620433 is 33402603235.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 47339750929 + 5890869504 = 217577^2 + 76752^2 .

It is a cyclic number.

It is not a de Polignac number, because 53230620433 - 213 = 53230612241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53230620395 and 53230620404.

It is not a weakly prime, because it can be changed into another prime (53230620403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26615310216 + 26615310217.

It is an arithmetic number, because the mean of its divisors is an integer number (26615310217).

Almost surely, 253230620433 is an apocalyptic number.

It is an amenable number.

53230620433 is a deficient number, since it is larger than the sum of its proper divisors (1).

53230620433 is an equidigital number, since it uses as much as digits as its factorization.

53230620433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 31.

The spelling of 53230620433 in words is "fifty-three billion, two hundred thirty million, six hundred twenty thousand, four hundred thirty-three".