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5323145201501 = 10495074494949
BaseRepresentation
bin100110101110110010000…
…1011011100011101011101
3200211212222010211012202112
41031131210023130131131
51144203300132422001
615153230311403405
71056404333440211
oct115354413343535
920755863735675
105323145201501
111772595768266
1271b7b2683565
132c7c80090a7a
141458da7b2941
1593701d22cbb
hex4d7642dc75d

5323145201501 has 4 divisors (see below), whose sum is σ = 5328219697500. Its totient is φ = 5318070705504.

The previous prime is 5323145201477. The next prime is 5323145201533. The reversal of 5323145201501 is 1051025413235.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3301757921476 + 2021387280025 = 1817074^2 + 1421755^2 .

It is a cyclic number.

It is not a de Polignac number, because 5323145201501 - 214 = 5323145185117 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5323145201201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2537246426 + ... + 2537248523.

It is an arithmetic number, because the mean of its divisors is an integer number (1332054924375).

Almost surely, 25323145201501 is an apocalyptic number.

It is an amenable number.

5323145201501 is a deficient number, since it is larger than the sum of its proper divisors (5074495999).

5323145201501 is a wasteful number, since it uses less digits than its factorization.

5323145201501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5074495998.

The product of its (nonzero) digits is 18000, while the sum is 32.

The spelling of 5323145201501 in words is "five trillion, three hundred twenty-three billion, one hundred forty-five million, two hundred one thousand, five hundred one".

Divisors: 1 1049 5074494949 5323145201501