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53232121333 = 106031502043
BaseRepresentation
bin110001100100111000…
…011011010111110101
312002101211121221120101
4301210320123113311
51333004410340313
640242101034101
73563066365006
oct614470332765
9162354557511
1053232121333
1120637165706
12a3973b5931
135034576c61
14280dabb1ad
1515b84da5dd
hexc64e1b5f5

53232121333 has 4 divisors (see below), whose sum is σ = 53232729408. Its totient is φ = 53231513260.

The previous prime is 53232121331. The next prime is 53232121337. The reversal of 53232121333 is 33312123235.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 53232121333 - 21 = 53232121331 is a prime.

It is a super-2 number, since 2×532321213332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53232121331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144991 + ... + 357052.

It is an arithmetic number, because the mean of its divisors is an integer number (13308182352).

Almost surely, 253232121333 is an apocalyptic number.

It is an amenable number.

53232121333 is a deficient number, since it is larger than the sum of its proper divisors (608075).

53232121333 is a wasteful number, since it uses less digits than its factorization.

53232121333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 608074.

The product of its digits is 9720, while the sum is 28.

Adding to 53232121333 its reverse (33312123235), we get a palindrome (86544244568).

The spelling of 53232121333 in words is "fifty-three billion, two hundred thirty-two million, one hundred twenty-one thousand, three hundred thirty-three".

Divisors: 1 106031 502043 53232121333