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532325403413 is a prime number
BaseRepresentation
bin1111011111100010001…
…00010000101100010101
31212220000200011100101222
413233301010100230111
532210200300402123
61044314044500125
753313343162106
oct7576104205425
91786020140358
10532325403413
111958378a3531
128720284a645
133b276210a0b
141ba9c4303ad
15dca899a6c8
hex7bf1110b15

532325403413 has 2 divisors, whose sum is σ = 532325403414. Its totient is φ = 532325403412.

The previous prime is 532325403409. The next prime is 532325403431. The reversal of 532325403413 is 314304523235.

Together with next prime (532325403431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 464609914129 + 67715489284 = 681623^2 + 260222^2 .

It is a cyclic number.

It is not a de Polignac number, because 532325403413 - 22 = 532325403409 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (532325103413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266162701706 + 266162701707.

It is an arithmetic number, because the mean of its divisors is an integer number (266162701707).

Almost surely, 2532325403413 is an apocalyptic number.

It is an amenable number.

532325403413 is a deficient number, since it is larger than the sum of its proper divisors (1).

532325403413 is an equidigital number, since it uses as much as digits as its factorization.

532325403413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 532325403413 its reverse (314304523235), we get a palindrome (846629926648).

The spelling of 532325403413 in words is "five hundred thirty-two billion, three hundred twenty-five million, four hundred three thousand, four hundred thirteen".