Base | Representation |
---|---|
bin | 100110101110110111001… |
… | …0100010101011001101010 |
3 | 200211220101222220022120122 |
4 | 1031131232110111121222 |
5 | 1144204122204212132 |
6 | 15153255225323242 |
7 | 1056411500334041 |
oct | 115355624253152 |
9 | 20756358808518 |
10 | 5323315304042 |
11 | 177267278a87a |
12 | 71b83b636522 |
13 | 2c7ca93aa968 |
14 | 145915211558 |
15 | 93711c23912 |
hex | 4d76e51566a |
5323315304042 has 4 divisors (see below), whose sum is σ = 7984972956066. Its totient is φ = 2661657652020.
The previous prime is 5323315304029. The next prime is 5323315304071. The reversal of 5323315304042 is 2404035133235.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 5319531700921 + 3783603121 = 2306411^2 + 61511^2 .
It is a junction number, because it is equal to n+sod(n) for n = 5323315303993 and 5323315304011.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1330828826009 + ... + 1330828826012.
Almost surely, 25323315304042 is an apocalyptic number.
5323315304042 is a deficient number, since it is larger than the sum of its proper divisors (2661657652024).
5323315304042 is a wasteful number, since it uses less digits than its factorization.
5323315304042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2661657652023.
The product of its (nonzero) digits is 129600, while the sum is 35.
The spelling of 5323315304042 in words is "five trillion, three hundred twenty-three billion, three hundred fifteen million, three hundred four thousand, forty-two".
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