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5323352513055 = 35973658661521
BaseRepresentation
bin100110101110111000010…
…0010010001101000011111
3200211220111120220201202020
41031131300202101220133
51144204211220404210
615153303035031223
71056412431526113
oct115356042215037
920756446821666
105323352513055
111772691794525
1271b84bb9b513
132c7cb4008025
1414591a139743
1593715123770
hex4d770891a1f

5323352513055 has 16 divisors (see below), whose sum is σ = 8605171899744. Its totient is φ = 2809852047360.

The previous prime is 5323352513053. The next prime is 5323352513099. The reversal of 5323352513055 is 5503152533235.

It is not a de Polignac number, because 5323352513055 - 21 = 5323352513053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5323352512998 and 5323352513016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5323352513053) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1829329306 + ... + 1829332215.

It is an arithmetic number, because the mean of its divisors is an integer number (537823243734).

Almost surely, 25323352513055 is an apocalyptic number.

5323352513055 is a deficient number, since it is larger than the sum of its proper divisors (3281819386689).

5323352513055 is a wasteful number, since it uses less digits than its factorization.

5323352513055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3658661626.

The product of its (nonzero) digits is 1012500, while the sum is 42.

The spelling of 5323352513055 in words is "five trillion, three hundred twenty-three billion, three hundred fifty-two million, five hundred thirteen thousand, fifty-five".

Divisors: 1 3 5 15 97 291 485 1455 3658661521 10975984563 18293307605 54879922815 354890167537 1064670502611 1774450837685 5323352513055