Base | Representation |
---|---|
bin | 100110101110111000010… |
… | …0010010001101000011111 |
3 | 200211220111120220201202020 |
4 | 1031131300202101220133 |
5 | 1144204211220404210 |
6 | 15153303035031223 |
7 | 1056412431526113 |
oct | 115356042215037 |
9 | 20756446821666 |
10 | 5323352513055 |
11 | 1772691794525 |
12 | 71b84bb9b513 |
13 | 2c7cb4008025 |
14 | 14591a139743 |
15 | 93715123770 |
hex | 4d770891a1f |
5323352513055 has 16 divisors (see below), whose sum is σ = 8605171899744. Its totient is φ = 2809852047360.
The previous prime is 5323352513053. The next prime is 5323352513099. The reversal of 5323352513055 is 5503152533235.
It is not a de Polignac number, because 5323352513055 - 21 = 5323352513053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5323352512998 and 5323352513016.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5323352513053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1829329306 + ... + 1829332215.
It is an arithmetic number, because the mean of its divisors is an integer number (537823243734).
Almost surely, 25323352513055 is an apocalyptic number.
5323352513055 is a deficient number, since it is larger than the sum of its proper divisors (3281819386689).
5323352513055 is a wasteful number, since it uses less digits than its factorization.
5323352513055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3658661626.
The product of its (nonzero) digits is 1012500, while the sum is 42.
The spelling of 5323352513055 in words is "five trillion, three hundred twenty-three billion, three hundred fifty-two million, five hundred thirteen thousand, fifty-five".
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