Base | Representation |
---|---|
bin | 100110101110111001110… |
… | …0010111101011011110001 |
3 | 200211220122002221221220011 |
4 | 1031131303202331123301 |
5 | 1144204312133232423 |
6 | 15153312041414521 |
7 | 1056413614052506 |
oct | 115356342753361 |
9 | 20756562857804 |
10 | 5323403024113 |
11 | 17727082541a9 |
12 | 71b864a9a441 |
13 | 2c7cc1611c25 |
14 | 145922b274ad |
15 | 9371979eb0d |
hex | 4d7738bd6f1 |
5323403024113 has 4 divisors (see below), whose sum is σ = 5358657348928. Its totient is φ = 5288148699300.
The previous prime is 5323403024099. The next prime is 5323403024119. The reversal of 5323403024113 is 3114203043235.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5323403024113 - 225 = 5323369469681 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5323403024119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17627162181 + ... + 17627162482.
It is an arithmetic number, because the mean of its divisors is an integer number (1339664337232).
Almost surely, 25323403024113 is an apocalyptic number.
It is an amenable number.
5323403024113 is a deficient number, since it is larger than the sum of its proper divisors (35254324815).
5323403024113 is a wasteful number, since it uses less digits than its factorization.
5323403024113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35254324814.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 5323403024113 its reverse (3114203043235), we get a palindrome (8437606067348).
The spelling of 5323403024113 in words is "five trillion, three hundred twenty-three billion, four hundred three million, twenty-four thousand, one hundred thirteen".
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