Base | Representation |
---|---|
bin | 1111011111101011110… |
… | …11101110001100011001 |
3 | 1212220020100210110212220 |
4 | 13233311323232030121 |
5 | 32210332201113113 |
6 | 1044330122454253 |
7 | 53315354156604 |
oct | 7576573561431 |
9 | 1786210713786 |
10 | 532407051033 |
11 | 19587999a600 |
12 | 87226064389 |
13 | 3b28a0ca010 |
14 | 1baa920533b |
15 | dcb0c27523 |
hex | 7bf5eee319 |
532407051033 has 48 divisors (see below), whose sum is σ = 849740532480. Its totient is φ = 294503235840.
The previous prime is 532407051013. The next prime is 532407051049. The reversal of 532407051033 is 330150704235.
It is not a de Polignac number, because 532407051033 - 213 = 532407042841 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 532407050985 and 532407051003.
It is not an unprimeable number, because it can be changed into a prime (532407051013) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 213841 + ... + 1053822.
It is an arithmetic number, because the mean of its divisors is an integer number (17702927760).
Almost surely, 2532407051033 is an apocalyptic number.
It is an amenable number.
532407051033 is a deficient number, since it is larger than the sum of its proper divisors (317333481447).
532407051033 is a wasteful number, since it uses less digits than its factorization.
532407051033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1267790 (or 1267779 counting only the distinct ones).
The product of its (nonzero) digits is 37800, while the sum is 33.
Adding to 532407051033 its reverse (330150704235), we get a palindrome (862557755268).
The spelling of 532407051033 in words is "five hundred thirty-two billion, four hundred seven million, fifty-one thousand, thirty-three".
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