Base | Representation |
---|---|
bin | 110001100101011110… |
… | …001010101000001111 |
3 | 12002102112020120001201 |
4 | 301211132022220033 |
5 | 1333014423423343 |
6 | 40243053050331 |
7 | 3563246440156 |
oct | 614536125017 |
9 | 162375216051 |
10 | 53242014223 |
11 | 20641802352 |
12 | a39a7869a7 |
13 | 503662bb38 |
14 | 281113459d |
15 | 15b92e194d |
hex | c6578aa0f |
53242014223 has 2 divisors, whose sum is σ = 53242014224. Its totient is φ = 53242014222.
The previous prime is 53242014169. The next prime is 53242014269. The reversal of 53242014223 is 32241024235.
53242014223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53242014223 - 225 = 53208459791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53242014191 and 53242014200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53242014923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26621007111 + 26621007112.
It is an arithmetic number, because the mean of its divisors is an integer number (26621007112).
Almost surely, 253242014223 is an apocalyptic number.
53242014223 is a deficient number, since it is larger than the sum of its proper divisors (1).
53242014223 is an equidigital number, since it uses as much as digits as its factorization.
53242014223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 28.
Adding to 53242014223 its reverse (32241024235), we get a palindrome (85483038458).
The spelling of 53242014223 in words is "fifty-three billion, two hundred forty-two million, fourteen thousand, two hundred twenty-three".
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