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532440539 is a prime number
BaseRepresentation
bin11111101111000…
…110010111011011
31101002212210002222
4133233012113123
52042301044124
6124500014255
716123445531
oct3757062733
91332783088
10532440539
11253604504
1212a39138b
1386402b97
14509dc151
1531b2525e
hex1fbc65db

532440539 has 2 divisors, whose sum is σ = 532440540. Its totient is φ = 532440538.

The previous prime is 532440529. The next prime is 532440541. The reversal of 532440539 is 935044235.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-532440539 is a prime.

It is a super-2 number, since 2×5324405392 = 566985855141221042, which contains 22 as substring.

Together with 532440541, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 532440499 and 532440508.

It is not a weakly prime, because it can be changed into another prime (532440529) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266220269 + 266220270.

It is an arithmetic number, because the mean of its divisors is an integer number (266220270).

Almost surely, 2532440539 is an apocalyptic number.

532440539 is a deficient number, since it is larger than the sum of its proper divisors (1).

532440539 is an equidigital number, since it uses as much as digits as its factorization.

532440539 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

The square root of 532440539 is about 23074.6731071103. The cubic root of 532440539 is about 810.5075003844.

The spelling of 532440539 in words is "five hundred thirty-two million, four hundred forty thousand, five hundred thirty-nine".