Search a number
-
+
532443324401 = 1731320195553
BaseRepresentation
bin1111011111110000001…
…10000101111111110001
31212220022220001100120222
413233320012011333301
532210420442340101
61044333500142425
753316304404062
oct7577006057761
91786286040528
10532443324401
1119589841529a
1287236237a15
133b29478a551
141baadd68569
15dcb3ee001b
hex7bf8185ff1

532443324401 has 4 divisors (see below), whose sum is σ = 563763519972. Its totient is φ = 501123128832.

The previous prime is 532443324353. The next prime is 532443324461. The reversal of 532443324401 is 104423344235.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 486089234401 + 46354090000 = 697201^2 + 215300^2 .

It is a cyclic number.

It is not a de Polignac number, because 532443324401 - 214 = 532443308017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (532443324461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15660097760 + ... + 15660097793.

It is an arithmetic number, because the mean of its divisors is an integer number (140940879993).

Almost surely, 2532443324401 is an apocalyptic number.

It is an amenable number.

532443324401 is a deficient number, since it is larger than the sum of its proper divisors (31320195571).

532443324401 is a wasteful number, since it uses less digits than its factorization.

532443324401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31320195570.

The product of its (nonzero) digits is 138240, while the sum is 35.

Adding to 532443324401 its reverse (104423344235), we get a palindrome (636866668636).

The spelling of 532443324401 in words is "five hundred thirty-two billion, four hundred forty-three million, three hundred twenty-four thousand, four hundred one".

Divisors: 1 17 31320195553 532443324401