Base | Representation |
---|---|
bin | 110001100101100111… |
… | …000011100010110101 |
3 | 12002102200121221121022 |
4 | 301211213003202311 |
5 | 1333021023011001 |
6 | 40243215030525 |
7 | 3563305314035 |
oct | 614547034265 |
9 | 162380557538 |
10 | 53244344501 |
11 | 206430540a7 |
12 | a39b50b445 |
13 | 5036c666ba |
14 | 281157d8c5 |
15 | 15b960211b |
hex | c659c38b5 |
53244344501 has 2 divisors, whose sum is σ = 53244344502. Its totient is φ = 53244344500.
The previous prime is 53244344497. The next prime is 53244344507. The reversal of 53244344501 is 10544344235.
53244344501 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52741419025 + 502925476 = 229655^2 + 22426^2 .
It is a cyclic number.
It is not a de Polignac number, because 53244344501 - 22 = 53244344497 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53244344507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26622172250 + 26622172251.
It is an arithmetic number, because the mean of its divisors is an integer number (26622172251).
Almost surely, 253244344501 is an apocalyptic number.
It is an amenable number.
53244344501 is a deficient number, since it is larger than the sum of its proper divisors (1).
53244344501 is an equidigital number, since it uses as much as digits as its factorization.
53244344501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 35.
Adding to 53244344501 its reverse (10544344235), we get a palindrome (63788688736).
The spelling of 53244344501 in words is "fifty-three billion, two hundred forty-four million, three hundred forty-four thousand, five hundred one".
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