53250032531 has 4 divisors (see below), whose sum is σ = 53891599272. Its totient is φ = 52608465792.

The previous prime is 53250032519. The next prime is 53250032543. The reversal of 53250032531 is 13523005235.

53250032531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13523005235 = 5 ⋅2704601047.

It is an interprime number because it is at equal distance from previous prime (53250032519) and next prime (53250032543).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53250032531 is a prime.

It is a super-2 number, since 2×53250032531² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53250032494 and 53250032503.

It is not an unprimeable number, because it can be changed into a prime (53270032531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 320783246 + ... + 320783411.

It is an arithmetic number, because the mean of its divisors is an integer number (13472899818).

Almost surely, 2^53250032531 is an apocalyptic number.

53250032531 is a deficient number, since it is larger than the sum of its proper divisors (641566741).

53250032531 is an equidigital number, since it uses as much as digits as its factorization.

53250032531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 641566740.

The product of its (nonzero) digits is 13500, while the sum is 29.

Adding to 53250032531 its reverse (13523005235), we get a palindrome (66773037766).

The spelling of 53250032531 in words is "fifty-three billion, two hundred fifty million, thirty-two thousand, five hundred thirty-one".