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53250837 = 317750279
BaseRepresentation
bin1100101100100…
…0101100010101
310201012102102020
43023020230111
5102113011322
65141203353
71214424153
oct313105425
9121172366
1053250837
1128071162
1215a00559
13b055c93
1471023d3
154a1d05c
hex32c8b15

53250837 has 4 divisors (see below), whose sum is σ = 71001120. Its totient is φ = 35500556.

The previous prime is 53250833. The next prime is 53250893. The reversal of 53250837 is 73805235.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53250837 - 22 = 53250833 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53250798 and 53250807.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53250833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8875137 + ... + 8875142.

It is an arithmetic number, because the mean of its divisors is an integer number (17750280).

Almost surely, 253250837 is an apocalyptic number.

It is an amenable number.

53250837 is a deficient number, since it is larger than the sum of its proper divisors (17750283).

53250837 is a wasteful number, since it uses less digits than its factorization.

53250837 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17750282.

The product of its (nonzero) digits is 25200, while the sum is 33.

The square root of 53250837 is about 7297.3171097329. The cubic root of 53250837 is about 376.2202313435.

The spelling of 53250837 in words is "fifty-three million, two hundred fifty thousand, eight hundred thirty-seven".

Divisors: 1 3 17750279 53250837