Base | Representation |
---|---|
bin | 100110101111101101010… |
… | …1110101001111000110111 |
3 | 200212002002202100220121122 |
4 | 1031133122232221320313 |
5 | 1144221333320034111 |
6 | 15154155521334155 |
7 | 1056504534243443 |
oct | 115373256517067 |
9 | 20762082326548 |
10 | 5325134143031 |
11 | 177341644149a |
12 | 72006879735b |
13 | 2c8209165851 |
14 | 145a489cd823 |
15 | 937bb74dcdb |
hex | 4d7daba9e37 |
5325134143031 has 2 divisors, whose sum is σ = 5325134143032. Its totient is φ = 5325134143030.
The previous prime is 5325134143027. The next prime is 5325134143061. The reversal of 5325134143031 is 1303414315235.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5325134143031 - 22 = 5325134143027 is a prime.
It is a super-2 number, since 2×53251341430312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5325134142982 and 5325134143000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5325134143061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662567071515 + 2662567071516.
It is an arithmetic number, because the mean of its divisors is an integer number (2662567071516).
Almost surely, 25325134143031 is an apocalyptic number.
5325134143031 is a deficient number, since it is larger than the sum of its proper divisors (1).
5325134143031 is an equidigital number, since it uses as much as digits as its factorization.
5325134143031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 5325134143031 its reverse (1303414315235), we get a palindrome (6628548458266).
The spelling of 5325134143031 in words is "five trillion, three hundred twenty-five billion, one hundred thirty-four million, one hundred forty-three thousand, thirty-one".
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