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5325154141 = 71731027427
BaseRepresentation
bin1001111010110011…
…10110011101011101
3111202010012212012011
410331121312131131
541401214413031
62240224311221
7245651030506
oct47531663535
914663185164
105325154141
112292a0213a
121047472511
1366b325aa8
14387341bad
152127836b1
hex13d67675d

5325154141 has 8 divisors (see below), whose sum is σ = 5474136384. Its totient is φ = 5178227040.

The previous prime is 5325154139. The next prime is 5325154147. The reversal of 5325154141 is 1414515235.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5325154141 - 21 = 5325154139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5325154147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 508531 + ... + 518896.

It is an arithmetic number, because the mean of its divisors is an integer number (684267048).

Almost surely, 25325154141 is an apocalyptic number.

It is an amenable number.

5325154141 is a deficient number, since it is larger than the sum of its proper divisors (148982243).

5325154141 is a wasteful number, since it uses less digits than its factorization.

5325154141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1027571.

The product of its digits is 12000, while the sum is 31.

The square root of 5325154141 is about 72973.6537457184. The cubic root of 5325154141 is about 1746.2673246765.

Adding to 5325154141 its reverse (1414515235), we get a palindrome (6739669376).

The spelling of 5325154141 in words is "five billion, three hundred twenty-five million, one hundred fifty-four thousand, one hundred forty-one".

Divisors: 1 71 73 5183 1027427 72947317 75002171 5325154141