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532532782841 is a prime number
BaseRepresentation
bin1111011111111010110…
…11010110011011111001
31212220120010101022111112
413233331123112123321
532211111343022331
61044350413410105
753321441652623
oct7577533263371
91786503338445
10532532782841
11195933966794
1287260199935
133b2aa17cb37
141babbbb3c13
15dcbbcb132b
hex7bfd6d66f9

532532782841 has 2 divisors, whose sum is σ = 532532782842. Its totient is φ = 532532782840.

The previous prime is 532532782807. The next prime is 532532782843. The reversal of 532532782841 is 148287235235.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 518061655225 + 14471127616 = 719765^2 + 120296^2 .

It is a cyclic number.

It is not a de Polignac number, because 532532782841 - 214 = 532532766457 is a prime.

Together with 532532782843, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 532532782841.

It is not a weakly prime, because it can be changed into another prime (532532782843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266266391420 + 266266391421.

It is an arithmetic number, because the mean of its divisors is an integer number (266266391421).

Almost surely, 2532532782841 is an apocalyptic number.

It is an amenable number.

532532782841 is a deficient number, since it is larger than the sum of its proper divisors (1).

532532782841 is an equidigital number, since it uses as much as digits as its factorization.

532532782841 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3225600, while the sum is 50.

The spelling of 532532782841 in words is "five hundred thirty-two billion, five hundred thirty-two million, seven hundred eighty-two thousand, eight hundred forty-one".