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53253433 is a prime number
BaseRepresentation
bin1100101100100…
…1010100111001
310201012112222101
43023021110321
5102113102213
65141223401
71214434552
oct313112471
9121175871
1053253433
1128073102
1215a01b61
13b05720c
147103329
154a1dbdd
hex32c9539

53253433 has 2 divisors, whose sum is σ = 53253434. Its totient is φ = 53253432.

The previous prime is 53253419. The next prime is 53253437. The reversal of 53253433 is 33435235.

53253433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30338064 + 22915369 = 5508^2 + 4787^2 .

It is a cyclic number.

It is not a de Polignac number, because 53253433 - 29 = 53252921 is a prime.

It is not a weakly prime, because it can be changed into another prime (53253437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26626716 + 26626717.

It is an arithmetic number, because the mean of its divisors is an integer number (26626717).

Almost surely, 253253433 is an apocalyptic number.

It is an amenable number.

53253433 is a deficient number, since it is larger than the sum of its proper divisors (1).

53253433 is an equidigital number, since it uses as much as digits as its factorization.

53253433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16200, while the sum is 28.

The square root of 53253433 is about 7297.4949811562. The cubic root of 53253433 is about 376.2263448740.

Adding to 53253433 its reverse (33435235), we get a palindrome (86688668).

The spelling of 53253433 in words is "fifty-three million, two hundred fifty-three thousand, four hundred thirty-three".