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53256433 is a prime number
BaseRepresentation
bin1100101100101…
…0000011110001
310201012201002111
43023022003301
5102113201213
65141245321
71214446366
oct313120361
9121181074
1053256433
112807538a
1215a03841
13b0586a9
14710446d
154a1ea3d
hex32ca0f1

53256433 has 2 divisors, whose sum is σ = 53256434. Its totient is φ = 53256432.

The previous prime is 53256323. The next prime is 53256451. The reversal of 53256433 is 33465235.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42419169 + 10837264 = 6513^2 + 3292^2 .

It is a cyclic number.

It is not a de Polignac number, because 53256433 - 29 = 53255921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53256395 and 53256404.

It is not a weakly prime, because it can be changed into another prime (53256473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26628216 + 26628217.

It is an arithmetic number, because the mean of its divisors is an integer number (26628217).

Almost surely, 253256433 is an apocalyptic number.

It is an amenable number.

53256433 is a deficient number, since it is larger than the sum of its proper divisors (1).

53256433 is an equidigital number, since it uses as much as digits as its factorization.

53256433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 32400, while the sum is 31.

The square root of 53256433 is about 7297.7005282486. The cubic root of 53256433 is about 376.2334095693.

It can be divided in two parts, 532 and 56433, that added together give a palindrome (56965).

The spelling of 53256433 in words is "fifty-three million, two hundred fifty-six thousand, four hundred thirty-three".